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LNGR SPKRHIFI. TWO WAYS. HANDCRAFTED.
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LNGR / ONLINE-WORKSHOP / Intermediate

Calculate and design speaker enclosures

An enclosure is part of the electroacoustic system, not just a wooden box. Work from outside dimensions to usable volume and learn what enclosure simulations can and cannot promise.

about 90–120 minutes6 lessonsNo login

Learning outcome: Build a volume budget, compare alignments and plan validation measurements.

LESSON 01 / 06

Outside dimensions are not volume

External measurements include the panels. For a plain rectangular closed cabinet, subtract twice the wall thickness from each dimension. Convert cubic millimetres to litres.

Worked example

Outside 260 × 400 × 280 mm, panels 18 mm: inside 224 × 364 × 244 mm, or 19.89 L gross internal space.

Your turn

What inside width results from 300 mm outside and 15 mm panels?

Reveal solution

270 mm. Subtract one panel on each side.

Which calculation is right?
LESSON 02 / 06

From internal gross to net volume

Drivers, braces, ducts and separate electronics compartments displace space. Net acoustic volume is internal space minus the occupied parts. Damping material may influence apparent compliance, but does not replace a volume budget.

Worked example

19.89 L internal minus 1.30 L drivers and braces and 0.70 L duct and fixtures yields 17.89 L net.

Your turn

What if you add a sealed 2 L internal compartment?

Reveal solution

Subtract another 2 L from the acoustically connected space.

Why subtract the port?
LESSON 03 / 06

Sealed: air acts as a spring

Trapped air behaves like a spring. Smaller box volume generally raises the system resonance; larger boxes approach the driver’s free-air behaviour. T/S parameters enable a first approximation.

Worked example

Ideal small-signal estimate: Qtc = Qts · √(1 + Vas/Vb). With Qts = 0.40, Vas = 20 L and Vb = 20 L, Qtc ≈ 0.57.

Your turn

What usually happens with much smaller Vb?

Reveal solution

Qtc and resonance increase, which alone does not define perceived bass quality.

What does the model require?
LESSON 04 / 06

Bass reflex: tuning, not magic

The air mass and friction in a port create a resonant system. Cross-sectional area, effective length and enclosure volume set Helmholtz tuning. Small ports may chuff; oversized ducts may become impractically long or develop resonances.

Worked example

A 40 Hz port tuning does not automatically imply a 40 Hz -3 dB point. The driver and alignment decide.

Your turn

Why check air velocity and cone travel?

Reveal solution

Fast airflow can become audible, and cone excursion can rise steeply below tuning.

Which statement is correct?
LESSON 05 / 06

Passive radiator: a tunable resonator

A passive radiator has no powered voice coil. Pressure inside the cabinet moves its diaphragm. Moving mass is central to tuning, and its excursion capability must be checked.

Worked example

Adding mass changes tuning. The correct mass depends on the active driver, box volume and the PR’s own mechanics.

Your turn

Why is area alone insufficient?

Reveal solution

Moving mass, suspension and excursion also matter.

What does a passive radiator normally lack?
LESSON 06 / 06

Build quality and validation

Joints should be airtight except for intended vents. Panels need appropriate stiffness; nothing should rattle. Validate the alignment with impedance and acoustic measurements rather than trusting a simulated plot alone.

Worked example

Checklist: record net volume, measure duct length, inspect leaks, take an impedance sweep, compare near-field and listening-position results.

Your turn

Which measurement reveals tuning especially well?

Reveal solution

A suitable impedance measurement, alongside acoustic sweeps.

What matters before listening tests?
INTERAKTIVES LABOR / INTERACTIVE LAB

Live enclosure volume budget

Plain rectangular cabinet with uniform panel thickness. Excludes unusual internal geometry.

Net volume—

Keep exploring

These are simplified educational models. Calculators do not replace datasheets or measurements. Your progress remains in this browser.