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LNGR SPKRHIFI. TWO WAYS. HANDCRAFTED.
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DSP: what it can and cannot fix

Digital signal processing is powerful for crossover filters, equalisation, delay and protection. It cannot repair poor mechanics or a spatial cancellation.

A processor is a tool, not a new loudspeaker

A DSP changes the numerical representation of an audio signal. It can adjust level, shape frequency response, delay a channel and apply dynamic limits. An analogue input needs conversion first; an analogue output needs conversion afterwards. None of this creates extra cone area or removes a mechanical limitation. Treat processing as a precise tool for a defined problem.

Equalise a cause you understand

A parametric EQ selects frequency, gain and bandwidth. A broad tonal imbalance needs a different correction from a narrow resonance. Begin with a repeatable raw measurement and a clear target. A dip seen at one microphone position may be interference rather than a deficiency in the loudspeaker. Automatic filter suggestions are a starting point for inspection, not a substitute for diagnosis.

Boost uses voltage and excursion

A 6 dB boost approximately doubles voltage and quadruples power into unchanged resistance. It can also demand much more cone excursion. Lowering input gain may create digital headroom, but the analogue output, amplifier input and driver still have their own limits. Conversely, an unnecessarily low DSP output can worsen the useful signal-to-noise ratio of the following chain.

Crossovers and timing

An active multiway system normally needs a separate amplifier channel for each processed way. Placing a DSP ahead of an existing passive loudspeaker does not remove its passive crossover. Delay can align contributions, but a tape-measure distance is only a starting point: filters, acoustic centres and electronics also affect phase. At 343 m/s, one metre corresponds to about 2.9 ms.

A deep null is not an invitation to boost

When contributions cancel, turning them both up does not remove the geometry causing cancellation. The driver may work harder while little improves at the seat. Test position, polarity and crossover alignment first. Reducing a repeatable peak is often more productive than filling a deep narrow null. Check nearby seats so one attractive trace does not conceal worse results elsewhere.

Limiters protect defined operating conditions

Peak limiting and long-term thermal protection are different tasks. A voltage ceiling alone does not describe cone excursion at every frequency. A suitable high-pass can reduce excessive low-frequency movement, especially below vented tuning, but frequency and slope must follow the driver, cabinet and intended use. Borrowed settings from another design do not provide reliable protection.

Choose a target and preserve the evidence

A ruler-flat in-room curve is not automatically the right target. Separate loudspeaker design from room-position correction, and inspect both direct response and behaviour off axis where appropriate. Save the raw measurement, filtered measurement and settings. Change one thing at a time and level-match listening comparisons. A useful preset should explain what it corrects and why it exists.

Explore the relationship
Interactive experiment

What does bass boost cost?

Increase boost from 3 to 6 dB. Voltage ratio approaches two; power demand into the same resistance approaches four.

Model limits: One boost operation into the same load. No specific equaliser, time-domain peak simulation or mechanical protection function.

A closer look · model and equation

Voltage factor = 10^(G/20); power factor = 10^(G/10). Remaining headroom here is a simplified level budget. Real EQ acts over a frequency region; peaks of the complete signal need separate checking.

Workshop takeaway

Create headroom before equalising. A limiter and high-pass need driver-specific settings; they are not blanket protection.

Work it out · answers unfold

Write down your prediction first, then your calculation. Open the answer only when you are ready to compare.

17 · A measured peak at 2 kHz is 4 dB above target. What voltage ratio is needed for ideal local correction?

Show worked answer
  1. Correction is -4 dB.
  2. Ratio = 10^(-4/20).
  3. Ratio = 0.6310; bandwidth and phase must also fit.
Calculation
k=10^{-4/20}=0.6310

18 · A deep dip comes from opposite-phase sound contributions. Why is strong EQ boost usually a poor first fix?

Show worked answer
  1. Cancellation remains.
  2. More drive increases excursion and power.
  3. First check polarity, delay, geometry and individual branches.

19 · Two ideal acoustic LR4 branches are each -6.02 dB at crossover and in phase. What is their sum?

Show worked answer
  1. Each branch has pressure ratio 0.5.
  2. Add in phase: 0.5 + 0.5 = 1.
  3. Sum = 0 dB.
Calculation
20\log_{10}(0.5+0.5)=0\,dB

20 · Plan a fair before-and-after test of a crossover correction. Name four conditions.

Show worked answer
  1. Same measurement position and excitation.
  2. Measure branches and sum with timing preserved.
  3. Check impedance and multiple angles; use identical smoothing.

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